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Zad. 1)
Dane:
r = 10
d = 2r
d = a√2
2r = a√2
20 = a√2
a = 20/√2
a = 10√2
Po = πr²
Po = 3,14*10²
Po = 3,14*100
Po = 314
Pk = a²
Pk =(10√2)²
Pk = 200
Pk/Po = 200/314
Pk/Po = 0,6
Odp: Stosunek pola kwadratu do pola koła wynosi 0,6.
Zad. 2)
Dane:
d = 10 cm
P = ? [cm²]
P = πR² - πr²
P = π(R² - r²)
R² - r² = 5²
R² - r² = 25
P = 25π cm²
Odp: Pole pierścienia wynosi 25π cm².