Question

1. Usuń niewymierność z mianownika:

a) 3

2√5 =

b) 4√3

√3+2 =

c) 2√5

3√2 -4 =

d) 4√2 -1

2√3+5 =

e) 4

\sqrt[3]{2} - 3 =

f) 5\sqrt{3}

\sqrt[3]{3} +2 =

Answer 1

a) 3/2√5 * √5/√5=3√5/2*5=3√5/10

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b) 4√3/[√3+2] * [√3-2]/[√3-2]=[4√3*(√3-2)]/[3-4]=[12-8√3]/-1=8√3-12

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c) 2√5/[3√2-4] * [3√2+4]/[3√2+4]=[6√10+8√5]/[18-16]=[6√10+8√5]/2=3√10+4√5

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d) [4√2-1]/[2√3+5] * [2√3-5]/[2√3-5]=[8√6-2√3-20√2+5]/[12-25]=[8√6-2√3-20√2+5]/13

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e) 4/[√(3/2)-3] * [√(3/2)+3]/[√(3/2)+3]=[4(√(3/2)+3)]/[3/2 - 9]=

=[4(√(3/2)+3)]/[15/2]=4(√(3/2)+3)*2/15=[8(√(3/2)+3)]/15