Question

1 soal doang
kak tolong dijawab dengan pembahasannya secepatnya.

Answer 1

Karena segitiga ABC adalah segitiga siku-siku, maka

∠A = 180° - 90° - 30°

∠A = 60°

BC/sin A = AC/sin B

20/sin 60° = AC/sin 30°

AC = ((20 . 1/2)/(1/2 √3)) . ((√3)/(√3))

AC = 20/3 . √3 cm

Luas

= 1/2 . AC . BC

= 1/2 . 20/3 √3 . 20

= 200/3 √3

= 115,47 cm²

= 115,5 cm²

Kelas 10

Pelajaran Matematika

Bab 6 Trigonometri Dasar

Kata kunci : sin

Kode kategorisasi : 10.2.6

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Answer 2

AC = k
AB = L
CB = m = 20 cm

berdasar aturan sinus.

AC/(sinus sudut B) = CB/(sinus sudut A)
AC/(sin 30°) = 20/(sin 60°)
AC/(½) = 20/(½√3)
AC = 20/√3 cm

maka luas ABC = AC × CB × ½
∆ABC = (20/√3)(20)(½)
∆ABC = 200/√3
∆ABC = 115,47
∆ABC = 115,5 cm² #A