1. sebuah persegi pnjng ABCD dgn pnjng AB=(5x+3)&AD=(5x+3)cm.bila luasnya 196cm.maka keliling nya adlh 2.bila keliling suatu persegi pnjng adlh a cm& lebarnya b cm , mka panjng nya adlh
Lisanurlyeni
1. AB x AD = Luas (5x + 3)(5x + 3) = 196 (5x + 3)² = 196 5x + 3 = √196 5x + 3 = 14 5x = 11 x = 2,2 kll = 2( 5x + 3 + 5x + 3) = 2(10x + 6) = 2 (10 . 2,2 + 6) = 56 cm
(5x + 3)(5x + 3) = 196
(5x + 3)² = 196
5x + 3 = √196
5x + 3 = 14
5x = 11
x = 2,2
kll = 2( 5x + 3 + 5x + 3)
= 2(10x + 6)
= 2 (10 . 2,2 + 6)
= 56 cm
2. kll = p x l
a = p x b
p = a/b cm