1. Sebuah benda tingginya 4 cm diletakkan di depan cermin cekung yang mempunyai jarak fokus 6 cm. Jarak benda terhadap cermin adalah 12 cm. a. Hitung jarak bayangan terhadap cermin b. Hitung perbesaran bayangan. 2. Sebuah cermin cembung memiliki jarak fokus 15 cm. Jika benda diletakkan pada jarak 10 cm di depan cermin, hitung jarak bayangan benda !!! ( jarak fokus bernilai negatif pada cermin cebung, f = -15 ).
NabilaCH
1. Diketahui : h = 4 cm f = 6 cm s = 12 cm Jawab : a) 1/f = 1/s + 1/s' 1/6 = 1/12 + 1/s' 1/6 - 1/12 = 1/s' 2/12 -1/12 = 1/s' 1/12 = 1/s' s' = 12 cm b) M = s'/s = 12/12 = 1 kali 2. Diketahui : f = 15 cm s = 10 cm Jawab : -1/f = 1/s + 1/s' -1/15 = 1/10 + 1/s' -1/15 - 1/10 = 1/s' -4/60 - 6/60 = 1/s' -10/60 = 1/s' -10s' = 60 s' = -6
h = 4 cm
f = 6 cm
s = 12 cm
Jawab :
a) 1/f = 1/s + 1/s'
1/6 = 1/12 + 1/s'
1/6 - 1/12 = 1/s'
2/12 -1/12 = 1/s'
1/12 = 1/s'
s' = 12 cm
b) M = s'/s
= 12/12
= 1 kali
2. Diketahui :
f = 15 cm
s = 10 cm
Jawab :
-1/f = 1/s + 1/s'
-1/15 = 1/10 + 1/s'
-1/15 - 1/10 = 1/s'
-4/60 - 6/60 = 1/s'
-10/60 = 1/s'
-10s' = 60
s' = -6