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Fx= 0
T1 cos 30°-T2cos60°=0
1/2√3 T1= 1/2 T2
T2= T1√3 …(1)
resultan gaya di sumbu y
Fx= 0
T1sin30°+T2sin60°-W=0
1/2T1+1/2√3 T2=30.10
1/2 T1+ 1/2√3 T2=300
substitusikan pers.1 ke pers. 2
» 1/2 T1+ 1/2 √3 (T1 √3)=300
2T1=300
T1= 150N
T2=T1√3
= 150 √3 N
mungkin begitu :))