Question

1) sebuah benda 10 cm di dpn cermin ckung yg jrak fkusx 8 cm . Htunglh
*Jarak byangan
*M
*sifat sifat byangan

2) sebuah bnda 15 cm di dpn crmin ckung yg R 24 cm .htunglh
*jrak byngan
*M

3) sebuah bnda 40 cm ddpn crmin ckung dngan f 20 cm htunglh
*jrak byangan
*M
*sfat sfat byngan

4) sebuah bnda 12 cm ddpn crmin ckung yg ttik fkusnya 18 cm ...htunglh
*jrak byngan
* M

Tlong djwb yh

Answer 1

1. Dik :
so = 10 cm
f = 8 cm

Dit : si, M, sifat bayangan
Jawab :
1/si = 1/f - 1/so
1/si = 1/8 - 1/10
1/si = 5/40 - 4/40
1/si = 1/40
si = 40 cm

M = si/so
M = 40/10
M = 4 cm

sifat bayangan = nyata, terbalik, dan diperbesar

2. Dik :
so = 15 cm
R = 2f = 24 cm
f = 12 cm

Dit : si, M
Jawab :
1/si = 1/f - 1/so
1/si = 1/12 - 1/15
1/si = 5/60 - 4/60
1/si = 1/60
si = 60 cm

M = si/so
M = 60/15
M = 4 cm

3. Dik :
so = 40 cm
f = 20 cm

Dit : si, M, sifat bayangan
Jawab :
1/si = 1/f - 1/so
1/si = 1/20 - 1/40
1/si = 2/40 - 1/40
1/si = 1/40
si = 40 cm

M = si/so
M = 40/40
M = 1

Sifat bayangan = nyata, terbalik, dan sama besar

4. Dik :
so = 12 cm
f = 18 cm

Dit : si, M
Jawab :
1/si = 1/f - 1/so
1/si = 1/18 - 1/12
1/si = 2/36 - 3/36
1/si = -1/36
si = -36 cm

M = si/so
M = 36/12
M = 3