" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
nNaOH = 15
[H⁺] = nHCl-nNaOH/Vcampuran
= 20-15/150
=3x10⁻²
pH = 2-log3
HCl = 100 x 0,2 = 20 mmol
NaOH= 50 x 0,3 = 15 mmol
M: 20 15
B: 15 15 15
S: 5 - 15
volume campuran= 100+50= 150
M= mmol
Vcamp
= 5 = 0,03 = 3x10pangkat-2
150
[H+] = a x M
= 1 x 3x10pangkat-2
= 3x10pangkat-2
pH = -log [H+]
= -log 3x10pangkat-2
= 2 - log 3
= 2 - 0,47
= 1,53