September 2018 2 35 Report

1. Rozwiąż równanie:

a) sinx=\frac{\sqrt{3}}{2}, x\in<-\pi; 2\pi>

b) cosx=-\frac{1}{2}, x\in<0; 3\pi>

2. Rozwiąż nierówność:

a) |cosx|<\frac{1}{2}, x\in<-\pi; \pi>

b) |sinx|\geqslant\frac{\sqrt{2}}{2}, x\in<0; 3\pi>


More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.