Question

1. persamaan garis yg melalui titik ( -2, 3) tegak lurus dengan y -3x=5

2. Persamaan garis yg melalui titik ( 3, 6) tegak lurus dengan 2y = 6× + 8

Answer 1

1. m1 x m2 = -1
-3 x m2 = -1
m2 = -1/-3
Diket, m= -1/-3, X1=-2, y1=3
y-y1=m(x-x1)
y-3=-1/3(x-(-2))
y-3=-1/3x-2/3
y=-1/3x-2/3+3
y=-1/3x-9/3
y=-1/3x-3

2. 2y/2=6x+8/2
y = 3/2+4/2
y = 7/2
m1xm2=-1
7/2xm2=-1
m2=-1:7/2
= -1x2/7
= -2/7
Diket, m=-2/7, x1=3, y1=6
y-y1=m(x-x1)
y-6=-2/7(x-3)
y-6=-2/7x+6/7
y=-2/7x+6/7+6
y=-2/7x+20/7
y=-2/7x+3 4/8