Question

1. persamaan garis melalui
A (-12,0) dan B (0,9) adalah 3bx+4ay=12ab tentukan axb
2. Tentukan persamaan garis melalui
(-3,7) dan sejajar dgn garis melalui A (8,-1) dan B (-2,3)

Answer 1

Verified answer

jawab

1. garis melalui A(-12,0) dan B(0,9)

y - y1 /y2-y1 = x - x1/ x2 - x1

y-0 / (9-0) = (x+12)/(0+12)

y /9 = (x +12)/12

12 y = 9x + 108

9x -12y = -108

3b = 9 dan b = 3

-12 = 4a dan a = - 3

a x b = 3 x -3 = - 9

2. Persmaan garis melalui (-3, 7) sejajar A(8,-1) dan B(-2,3)

m = (y2-y1)/x2 -x1

m= (3 +1)/(-2 -8) = 4/-10 = - 2/5

garis nya y - y1 = m (x - x1)

y - 7 = -2/5 (x + 3)

5(y -7) = -2(x + 3)

5y - 35 = -2x - 6

2x + 5y = 35 - 6

2x + 5y = 29

Answer 2

Persamaan garis

-12....0
0........9
Kurangkan
-12.....-9

-12(y - 0) = -9(x + 12)
9x - 12y = -108
3bx + 4ay = 12ab

12ab = -108
ab = -108/12
ab = -9 ✔

•••
m = (8 - (-2))/(-1 - 3) = 10/-4 = -5/2

PG melalui (-3,7)
y - 7 = -5/2 (x + 3)
5x + 2y - 14 + 15 = 0
5x + 2y + 1 = 0 ✔