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20² = j² - (9+6)²
20² = j² - 15²
400 = j² - 225
400 + 225 = j²
625 = j²
√625 = j
25 cm = j (jarak kedua pusat lingkaran)
20=√j²-(9+6)²
20²=j²-(15)²
400=j²-225
400+225=j²
j=√625
j=25 cm