1) Wzór glicyny:
NH₂-CH₂-COOH
m=14u+5u+24u+32u=75u
masa węgla w cząsteczce: 24u
x = 24u / 75u * 100% = 32% 2) 2C₄H₆ + 11O₂ →6H₂O + 8CO₂ 3) 2C₃H₃COOH + Na₂O→2C₃H₃COONa + H₂O
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1) Wzór glicyny:
NH₂-CH₂-COOH
m=14u+5u+24u+32u=75u
masa węgla w cząsteczce: 24u
x = 24u / 75u * 100% = 32%
2) 2C₄H₆ + 11O₂ →6H₂O + 8CO₂
3) 2C₃H₃COOH + Na₂O→2C₃H₃COONa + H₂O