Odpowiedź:
Zadanie 11
a)
(1/2x - 3)(1/3x - 2) dla x = -6
(1/2*(-6) - 3)(1/3*(-6) - 2) = (-3-3)(-2-2) = -6*(-4) = 24
b)
[tex]\frac{x^2y - y}{2x}[/tex] dla x = -2 i y = 8
[tex]\frac{(-2)^2*8-8}{2*(-2)}[/tex] = [tex]\frac{4*8-8}{-4}[/tex] = [tex]\frac{24}{-4}[/tex] = -6
Zadanie 12
(2 + x)(3 - x) = 6 - 2x - x^2 + 3x =-x^2 + x + 6
(3 + k)(4 - m) = 4k - 3m - mk + 12
c)
(5x - 2)(3x + 6) = 15x^2 - 6x + 30x - 12 = 15x^2 + 24x - 12
Zadanie 13
a) [tex](\sqrt{6} +2)(\sqrt{6} - 2 ) = 6 - 4 = 2[/tex]
b) [tex](\sqrt{7} - \sqrt{2})(\sqrt{2} + 2\sqrt{7}) = 14 - 2 +\sqrt{14} - 2\sqrt{14} = 12 - \sqrt{14}[/tex]
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Verified answer
Odpowiedź:
Zadanie 11
a)
(1/2x - 3)(1/3x - 2) dla x = -6
(1/2*(-6) - 3)(1/3*(-6) - 2) = (-3-3)(-2-2) = -6*(-4) = 24
b)
[tex]\frac{x^2y - y}{2x}[/tex] dla x = -2 i y = 8
[tex]\frac{(-2)^2*8-8}{2*(-2)}[/tex] = [tex]\frac{4*8-8}{-4}[/tex] = [tex]\frac{24}{-4}[/tex] = -6
Zadanie 12
a)
(2 + x)(3 - x) = 6 - 2x - x^2 + 3x =-x^2 + x + 6
b)
(3 + k)(4 - m) = 4k - 3m - mk + 12
c)
(5x - 2)(3x + 6) = 15x^2 - 6x + 30x - 12 = 15x^2 + 24x - 12
Zadanie 13
a) [tex](\sqrt{6} +2)(\sqrt{6} - 2 ) = 6 - 4 = 2[/tex]
b) [tex](\sqrt{7} - \sqrt{2})(\sqrt{2} + 2\sqrt{7}) = 14 - 2 +\sqrt{14} - 2\sqrt{14} = 12 - \sqrt{14}[/tex]
Pozdrawiam✌️