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1mol NaOH->23+16+1=40
ms=40
mr=130
Cp=ms/mr*100%
Cp=40/130*100%=30,8%
2) 10 moli H2O-> 10*18=180
1mol KOH-> 39+16+1=56
ms=56
mr=136
Cp=56/136*100%=41,2%