1) Oblicz pole powierzchni graniastosłupa prawidłowego trójkątnego jeśli krawędzi podstawy wynosi : 6 cm a wysokość 10 cm . ( Wszystkie obliczenia , daje naj )
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Pp =![\frac{a^{2}\sqrt{3}}{4} \frac{a^{2}\sqrt{3}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2%7D%5Csqrt%7B3%7D%7D%7B4%7D)
Pp =![\frac{6^{2}\sqrt{3}}{4} \frac{6^{2}\sqrt{3}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B6%5E%7B2%7D%5Csqrt%7B3%7D%7D%7B4%7D)
Pp =![\frac{36\sqrt{3}}{4} \frac{36\sqrt{3}}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B36%5Csqrt%7B3%7D%7D%7B4%7D)
![9\sqrt{3} 9\sqrt{3}](https://tex.z-dn.net/?f=9%5Csqrt%7B3%7D)
![9\sqrt{3} 9\sqrt{3}](https://tex.z-dn.net/?f=9%5Csqrt%7B3%7D)
+ 3 *a*b![18\sqrt{3} 18\sqrt{3}](https://tex.z-dn.net/?f=18%5Csqrt%7B3%7D)
+ 3 * 6cm * 10cm
Pp =
Pc = 2Pp + Pb
Pc = 2 *
Pc =
Pc =![18\sqrt{3} 18\sqrt{3}](https://tex.z-dn.net/?f=18%5Csqrt%7B3%7D)
+ 180![cm^{2} cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)