Question

1 Oblicz Cp roztworu powstałego przez dodanie 2g soli do 15g roztworu tej soli o Cp=15%

Answer 1

 

mr₁ = 15g

cp₁ = 15%

 

ms = mr x cp/100%

 

ms₁ = 15g x 15%/100% = 2,25g

 

ms₁ = 2,25g

 

ms₂ = 2,25g + 2g = 4,25g

mr₂ = 15g + 2g = 17g

 

cp₂ = 4,25g/17g x 100% = 25%

 

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Answer 2

Cp₁=15%

mr₁=15g

Cp=(ms*100%)/mr /*mr

Cp*mr=ms*100% /:100%

ms=(Cp*mr)/100%

ms₁=(Cp₁*mr₁)/100%

ms₁=(15%*15g)/100%=2,25g

ms₁=2,25g

ms₂=ms₁+2g

ms₂=2,25g+2g=4,25g

ms₂=4,25g

mr₂=mr₁+2g

mr₂=15g+2g=17g

mr₂=17g

Cp₂=(ms₂*100%)/mr₂

Cp₂=(4,25g*100%)/17g=25%

Cp₂=25%

 

Odp. Cp powstałego roztworu wynosi 25%.