1. Keliling alas sebuah kerucut 94,2 cm, jika kerucu tsb selimutnya mempunyai luas 471 cm, maka pjg garis pelukis kerucut dg pi 3,14 adalah ?
SILVINA
Keliling alas kerucut = 2 x phi x r 94,2 = 2 x 3,14 x r r = 94,2 / 6,28 = 15 cm selimut kerucut = phi x r x s 471 = 3,14 x 15 x s s = 471 : 47,1 = 10 cm
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lovemyfamily
> 94,2 = 2 x 3,14 x r = 6,28 r r = 94,2 / 6,28 = 15 cm > 471 = 3,14 x 15 x s = 47,1 s s = 471 / 47,1 = 10 cm BE HAPPY :D
94,2 = 2 x 3,14 x r
r = 94,2 / 6,28
= 15 cm
selimut kerucut = phi x r x s
471 = 3,14 x 15 x s
s = 471 : 47,1
= 10 cm
= 6,28 r
r = 94,2 / 6,28
= 15 cm
> 471 = 3,14 x 15 x s
= 47,1 s
s = 471 / 47,1
= 10 cm
BE HAPPY :D