1. Penyelesaian: Diket.: d = 12 cm r = ½d = ½.12 = 6 cm Ditanya: V = ....? Jawab: V = 4/3πr³ V = 4/3 × 3,14 × 6³ V = 4/3 × 3,14 × 216 V = 2712,96/3 V = 904,32 cm³
2. Penyelesaian: Diket.: r = 3 cm t = 4 cm Ditanya: Luas permukaan = ...? Jawab: s² = r² + t² s² = 3² + 4² s² = 9 + 16 s² = 25 s = √ 25 s = 5 cm
3. Penyelesaian: Diket.: d = 14 cm r = ½d = ½.14 = 7 cm t = 14 cm Ditanya: Luas permukaan = ....? Jawab: Luas permukaan = 2πr(r + t) = 2 × 22/7 × 7(7 + 14) = 308/7 × 21 = 6468/7 = 924 cm²
Verified answer
1.Penyelesaian:
Diket.:
d = 12 cm
r = ½d = ½.12 = 6 cm
Ditanya:
V = ....?
Jawab:
V = 4/3πr³
V = 4/3 × 3,14 × 6³
V = 4/3 × 3,14 × 216
V = 2712,96/3
V = 904,32 cm³
2.
Penyelesaian:
Diket.:
r = 3 cm
t = 4 cm
Ditanya:
Luas permukaan = ...?
Jawab:
s² = r² + t²
s² = 3² + 4²
s² = 9 + 16
s² = 25
s = √ 25
s = 5 cm
Luas permukaan
= πr(r + s)
= 3,14 × 3(3 + 5)
= 3,14 × 3 × 8
= 75,36 cm²
3.
Penyelesaian:
Diket.:
d = 14 cm
r = ½d = ½.14 = 7 cm
t = 14 cm
Ditanya:
Luas permukaan = ....?
Jawab:
Luas permukaan
= 2πr(r + t)
= 2 × 22/7 × 7(7 + 14)
= 308/7 × 21
= 6468/7
= 924 cm²
Semoga bisa membantu...