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Syarat tegak lurus = m1.m2 = -1
2y-3x+5 = 0
2y = 3x-5
m1 = 3/2
m2 = -1 / 3/2 = -2/3
No. 2
Diket : x1 = 2, y1 = 3, x2 = 1, y2 = -1
=> y-y1 / y2-y1 = x-x1 / x2-x1
=> y-3 / -1-3 = x-2 / 1-2
=> y-3 / -4 = x-2 / -1 (kali silang)
=> -y+3 = -4x+8
=> -y = -4x+5 (dibagi -1)
=> y = 4x-5
No 3 sama kaya No. 1
Good Luck! :D
2y = 3x -5
y = 3/2x -5/2
Maka, m₁ = 3/2
m₁ . m₂ = -1
3/2 . m₂ = -1
m₂ = -1 per 3/2
m₂ = -2/3
Jadi, gradien yang tegak lurus dengan garis 2y -3x +5 = 0 adalah -2/3.
2. Titik (2,3) dan (1,-1)
Persamaan :
y -y₁ = x -x₁
y₂ -y₁ x₂ -x₁
y -3 = x -2
-1 -3 1 -2
y -3 = x -2
-4 -1
-1(y -3) = -4(x -2)
-y +3 = -4x +8
-y = -4x +8 -3
-y = -4x +5
4x -y -5 = 0
3. 3x -4y -5 = 0
3x -5 = 4y
4y = 3x -5
y = 3/4x -5/4
Maka, m₁ = 3/4
m₁ . m₂ = -1
3/4 . m₂ = -1
m₂ = -1 per 3/4
m₂ = -4/3
Jadi, gradien garis h adalah -4/3.
Itu jawabannya.