Question

1. fungsi h dinyatakan dengan rumus h(x) = px + q, jika h(3) = 19 dan h(-2) = -16, maka h(11) =....
a. 77
b. 76
c. 75
d. 71

Answer 1

H(3)=3p+q=19
h(-2)=(-2)p+q= -16
p=7
q=-2
h(11)=11p+q=?
h(11)=11(7)+(-2)=?
h(11)=77+(-2)=75
yeeeeeee.........

Answer 2

h(x) = px + q
* h(3) = p(3) + q
  19 = 3p + q
   3p + q = 19
* h(-2) = p(-2) + 9
  -16 = -2p + q
   -2p + q = -16

Eliminasi
3p + q = 19
-2p + q = -16
-------------------- -
5p = 35
<=> p = 35/5
<=> p = 7
Subtitusi
3p + q = 19
3(7) + q = 19
21 + q = 19
<=> q = 19 - 21
<=> q = -2

h(11) = px + q
h(11) = 7(11) + (-2)
h(11) = 77 - 2
h(11) = 75

Jawaban C. 75
Semoga membantu ^_^