Explicación paso a paso:
Los cuatro (4) triángulos son rectángulos, por lo tanto se cumple el teorema de Pitágoras.
[tex] {h}^{2} = {cat1}^{2} + {cat2}^{2} [/tex]
Entonces:
a)
[tex]x = \sqrt{ {8}^{2} + {15}^{2} } = 17[/tex]
b)
[tex]x = \sqrt{ {10}^{2} - {6}^{2} } = 8[/tex]
c)
[tex]x = \sqrt{ {12}^{2} - {8}^{2} } = 8.94[/tex]
d)
[tex]x = \sqrt{ {4}^{2} + {(2 \sqrt{3}) }^{2} } [/tex]
[tex]x = \sqrt{16 + (4 \times 3)} [/tex]
[tex]x = \sqrt{16 + 12} [/tex]
[tex]x = \sqrt{28} = 5.29[/tex]
Respuesta:
a) X= 17.02
b) X= 8
c) X= 8.9
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Explicación paso a paso:
Los cuatro (4) triángulos son rectángulos, por lo tanto se cumple el teorema de Pitágoras.
[tex] {h}^{2} = {cat1}^{2} + {cat2}^{2} [/tex]
Entonces:
a)
[tex]x = \sqrt{ {8}^{2} + {15}^{2} } = 17[/tex]
b)
[tex]x = \sqrt{ {10}^{2} - {6}^{2} } = 8[/tex]
c)
[tex]x = \sqrt{ {12}^{2} - {8}^{2} } = 8.94[/tex]
d)
[tex]x = \sqrt{ {4}^{2} + {(2 \sqrt{3}) }^{2} } [/tex]
[tex]x = \sqrt{16 + (4 \times 3)} [/tex]
[tex]x = \sqrt{16 + 12} [/tex]
[tex]x = \sqrt{28} = 5.29[/tex]
Respuesta:
a) X= 17.02
b) X= 8
c) X= 8.9