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Efectuar.
x² - x - 6 = 0
Aplicamos el método del aspa simple.
x + 3
x - 2
(x + 3) (x - 2) = 0
Tenemos dos soluciones.
x + 3 = 0
x = - 3
...............................................................
x - 2 = 0
x = 2
.......................................................................
Solución.
(- 3 y 2).
a. b. c
-b± √b²-4ac/2a
sustituimos:
-(-1)±√(-1)²-4(1)(-6)/2(1)
1±√1+24/2
1±√25/2
1+5/2.........1-5/2
6/2.............-4/2
3..................-2
x1 =3, x2=-2