1. Doprowadź do najprostszej postaci wyrażenia korzystając ze wzorów skróconego mnożenia.
a)(x-5)²-3(x-1)(x+1)-(2x²-1)+x(2x-3)
b)(4+x)(4-x)-2x(1-3x)+(2(x+2)²-4(x²-1)
c)(x-2)²+3(4-x)(4+x)-2(2x+1)²
d)(x+3)²-2(3-x)(3+x)+4(3x-1)²
e)(2-x)(2+x)-4(2x-1)²+2(x+3)²
f)(5+x)(5-x)+3(3x+1)²-4(x-2)²
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a)(x-5)²-3(x-1)(x+1)-(2x²-1)+x(2x-3)=(x²-10x+25)-3(x²-1)-(2x²-1)+2x²-3x=x²-10x+25-3x²+3-2x²+1+2x²-3x=-2x²-13x+29
b)(4+x)(4-x)-2x(1-3x)+2(x+2)²-4(x²-1)=16-x²-2x+6x²+2(x²+4x+4)-4x²+4=16-x²-2x+6x²+2x²+8x+8-4x²+4=28+3x²+6x
c)(x-2)²+3(4-x)(4+x)-2(2x+1)²=x²-4x+4+3(16-x²)-2(4x²+4x+1)=x²-4x+4+48-3x²-8x²-8x-2=-10x²-12x+50
d)(x+3)²-2(3-x)(3+x)+4(3x-1)²=x²+6x+9-2(9-x²)+4(9x²-6x+1)=x²+6x+9-18+2x²+36x²-24x+4=39x²-18x-5
e)(2-x)(2+x)-4(2x-1)²+2(x+3)²=4-x²-4(4x²-4x+1)+2(x²+6x+9)=4-x²-16x²+16x-4+2x²+12x+18=18-15x²+28x
f)(5+x)(5-x)+3(3x+1)²-4(x-2)²=25-x²+3(9x²+6x+1)-4(x²-4x+4)=25-x²+27x²+18x+3-4x²+16x-16=12+22x²+34x
Na 100 procent dobrze zrobione.
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