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5x= 2a -1 /:5
{x= (2a -1)/5 ∧ x∈<-1, 4)} ⇔ -1 ≤ (2a -1)/5 <4 /·5
-5≤2a-1 <20 /+1
-4 ≤2a < 21 /:2
-2≤a < 10,5
Odp. a∈<-2, 10,5)
Zad.2. 2x +5 -a = 4x +2 / -2x, -2
3-a = 2x
2x= 3-a /:2
{x= ( 3-a)/2 ∧ x∈(-1, 3>} ⇔ -1< (3-a)/2 ≤3 /·2
-2< 3-a≤6 / -3
-5< -a ≤ 3/·(-1)
5> a ≥ -3
-3 ≤ a <5
Odp. a∈ < -3, 5)