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g2 -----> x + 2y - 4 = 0 --------->x2 --> 2x + 4y - 8 = 0
------------------- dikurangkan
- 5y + 12 = 0 ----> 5y = 12 -----> y = 12/5
2x-y + 4 = 0 ------> 2x -12/5 + 4 = 0 ----> 2x = - 8/5 ---> x= - 8/10 ----> x = - 4/5
jadi kedua garis berpotongan pda titik ( -4/5, 12/5)
2. garis yang sejajar dengan sumbu x gradiennya (m) = 0
jawaban c, melalui titik (0,3)