1. Diketahui luas alas sebuah balok 112 cm2, panjang balok 14 cm, dan tinggi nya 5 cm. Luas permukaan balok tersebut ... 2. Diketahui luas alas sisi depan suatu balok luasnya 72 cm2. Jika p : l : t = 6:4:3, maka volumenya ... 3. Alas sebuah prisma berbentuk persegi panjang dngn panjang 15 cm dan lebar 9 cm. Hitunglah luas permukaan prisma tersebut, jika tinggi prisma 20 cm ... tolong ya.. ;)
zahraaryoko
Nomor 1 La = p x l 112 = 14 x l l = 112 : 14 l = 8 cm
Maka; Lp = ( 2 x p x l ) + ( 2 x p x t ) + ( 2 x l x t ) Lp = ( 2 x 14 x 8 ) + ( 2 x 14 x 5 ) + ( 2 x 8 x 5 ) Lp = 224 + 140 + 80 Lp = 444 cm^2
========================================================= Nomor 2 La = p x t 72 = 6a x 3a 72 = 18a^2 a^2 = 4 a = 2
Maka; p = 6a = 6 x 2 = 12 cm l = 4a = 4 x 2 = 8 cm t = 3a = 3 x 2 = 6 cm Volume = 12 x 8 x 6 = 576 cm^3
========================================================= Nomor 3 ( 2 x La ) + ( Ka x T ) ( 2 x 15 x 9 ) + ( 2 x 15 + 2 x 9 x 20 ) 270 + ( 30 + 18 x 20 ) 270 + ( 48 x 20 ) 270 + 960 1230 cm^2
La = p x l
112 = 14 x l
l = 112 : 14
l = 8 cm
Maka;
Lp = ( 2 x p x l ) + ( 2 x p x t ) + ( 2 x l x t )
Lp = ( 2 x 14 x 8 ) + ( 2 x 14 x 5 ) + ( 2 x 8 x 5 )
Lp = 224 + 140 + 80
Lp = 444 cm^2
=========================================================
Nomor 2
La = p x t
72 = 6a x 3a
72 = 18a^2
a^2 = 4
a = 2
Maka;
p = 6a = 6 x 2 = 12 cm
l = 4a = 4 x 2 = 8 cm
t = 3a = 3 x 2 = 6 cm
Volume = 12 x 8 x 6 = 576 cm^3
=========================================================
Nomor 3
( 2 x La ) + ( Ka x T )
( 2 x 15 x 9 ) + ( 2 x 15 + 2 x 9 x 20 )
270 + ( 30 + 18 x 20 )
270 + ( 48 x 20 )
270 + 960
1230 cm^2