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Jawab1) P, R dan W hubungkan membentuk ΔPRW sama sisi
PR = RW = PW = diagonal sisi = 12√2
sama sisi , maka <P = <R = <W = 60°
buat T pada RW, sehingga PT tegak lurus RW
PT = PR sin < R
PT = 12√2 ( sin 60)
PT = 12√2 (1/2 √3)
PT = 6√6
2)
BC = a = 4
AB = c = 6
<B = 60°
AC = b
aturan cosinus
AC² = a² + c² = 2 ac cos 60
AC² = 4² + 6² - 2(4)(6)(1/2)
AC² = 16 + 36 - 24
AC² = 28
AC = 2√7
3)
PR = 10
<R = 45
<Q = 30
PQ = ..
PQ/sin R = PR/sin Q
PQ = PR. sin R / sin Q
PR = (10)(sin 45) / sin 30
PR = (10. 1/2 √2) / (1/2)
PR = 10 √2