1) dane sa odcinki AB i CD o dlugosciach: a) |AB|=10 cm |CD|=30 cm b)|AB|=12,5 dm |CD|=5dm c)|AB|=2,1 m |CD|=1,4 d)|AB|=30cm |CD|=5dm e)|AB|=4,2m |CD|=1,2dm f)|AB|=1 3\4cm |CD|=35mm oblicz stosunek dlugosci odcinkow AB i CD.
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a) = =
b) = = =
c) = =
d) |CD|= 5dm = 50cm
= =
e) |AB|= 4,2m = 42dm
= = 35
a/ 10/30=1:3
b/ 12,5/5=125/50=5:2
c/ 2,1/1,4=21/14=3:2
d/ 30cm=3dm
3/5=3:5
e/ 4,2m=42dm
42/1,2=420/12=35:1
f/ 1,2dm=12cm
12/7\4=48:7
myślę, że dobrze