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berapa luas pemukaan kerucut tersebut?
K. alas = π.d
44 = 22/7 . d
d= 7/22 . 44
d= 14
s(garis pekukis)= √t² + r² = √24² + 7² = √576 + 49 = √625 = 25
luas selimut = πrs = 22/7 . 7 . 25 = 550
lp = πr² + πrs
lp = 22/7.7² + 550
lp = 154 + 550
lp = 704