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=sin(45+x)*sin(135+x)/[cos(45+x)*cos(135+x)]
=[-1/2*(cos(180+2x)-cos(90))] / [1/2*(cos(180+2x)+cos(90))]
=-1*(-cos(2x))/(-cos(2x))
=-1
2. sin(123)cos(57)+cos(123)sin(57)=sin(123+57)=sin(180)=0
3.cos(80)cos(10)-sin(80)sin(10)=cos(80+10)=cos(90)=0