Question

1. berpakan molalitas 70% alkohol C2H5OH jika (mr : 46)

2. hitunglah molal larutan urea 15% (mr : 60)

Answer 1

1. gr alkohol = 70 , gr air = 30
m = gr alkohol / mr x 1000/ gr air

Answer 2

1. molal alkohol = gr/mr x 1000/p
= 70/46 x 1000/30
= 50,72


2. molal urea = gr/mr x 1000/p
= 15/60 x 1000/40
=6,25