" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2. (2a + 3b - c) - (a - 6b + 5c) = 2a -a + 3b + 6b - c - 5c = c. a + 9b - 6c
3. pemfaktoran = c.2pq(3q-2p) (FPB=2Pq)
Misalnya nama himpunannya A, maka :
A= {januari, februari, mei, mei, juni, juli}
n(A)= 5
(C)
No. 2
(2a + 3b - c) - (a - 6b + 5c)
2a + 3b - c - a + 6b - 5c
2a - a + 3b + 6b - c - 5c
a + 9b - 6c (C)
No. 3
6pq² - 4p²q
2pq(3q - 2p) (C)