1. Alas sebuah prisma berbentuk belah ketupat dengan panjang diagonalnya 16 cm dan 30 cm.Jika luas permukaan prisma 820 cm2.hitunglah volume prisma tersebut.
SilaFarsidia
Volume prsma : la x t : (d1 x d2 /2) x ((luas permukaan- (luas alas+luas atap)) : keliling alas) : (16 x 30/2) x ((820 - (240+240)) : (17x4)) : 240 x (340:68) :240 x 5 :1200 cm³
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Ridafahmi
S² = (16/2)² + (30/2)² = 64 + 225 = 289 s = √289 = 17 cm
L prisma = (2×) + (4s × t) 820 = (2×) + (4×17×t) = 480 + 68t 68t = 820 - 480 = 340 t = 340/68 = 5 cm
: (d1 x d2 /2) x ((luas permukaan- (luas alas+luas atap)) : keliling alas)
: (16 x 30/2) x ((820 - (240+240)) : (17x4))
: 240 x (340:68)
:240 x 5
:1200 cm³
= 64 + 225
= 289
s = √289
= 17 cm
L prisma = (2×) + (4s × t)
820 = (2×) + (4×17×t)
= 480 + 68t
68t = 820 - 480
= 340
t = 340/68
= 5 cm
V prisma belah ketupat = 1/2 × 16 × 30 × 5 cm³
= 1200 cm³