Question

1. akar-akar persamaan
kuadrat 6x²-5x=0
adalah.....

2. apabila akar-akar
persamaan x²+3x-1=0
x1 dan x2² adalah...

tolong bantu ya..

Answer 1

1) 6x²-5x=0
X(6x - 5) = 0
X = 0
6x - 5 = 0
6x = 5
X = 5/6

Hp : {0, 5/6}

2) x² + 3x - 1 = 0
A = 1
B = 3
C = -1

X1,X2 = (-B ± √b² - 4ac)/2a
X1,X2 = (-3 ± √3² - 4(1)(-1))/2
X1,X2 = (-3 ± √9 + 4)/2
X1,X2 = (-3 ± √13)/2

X1 = (-3 ± √13)/2
X2 = (-3 - √13)/2