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V₁ = 0,001 m³ = 10⁻³ m³
α = 0,00001 /°C = 10⁻⁵ /°C
Ditanya : V₂ pada T₂ = 100 °C
Jawab : V₂ = V₁ (1+γ×ΔT)
V₂ = V₁ (1+3α×(T₂-T₁))
V₂ = 10⁻³ (1+3·10⁻⁵×(100-0))
V₂ = 10⁻³ (1+3·10⁻⁵×100)
V₂ = 10⁻³ (1+3·10⁻³)
V₂ = 10⁻³ (1+3·0,001)
V₂ = 10⁻³ (1+0,003)
V₂ = 10⁻³ (1,003)
V₂ = 0,001×(1,003)
V₂ = 0,001003 m³